Question

For what value of p the quadratic equation px (x-4)+64=6 has equal roots p not equal to zero.

Answer 1

Answer:

px(x-3) + 9 = 0

px2-3px+9=0

a=p , b=-3p , c=9

b2-4ac= (-3p)2-4(p)(9)

=9p2-36p

for having equal roots  

b2-4ac = 9p2-36p = 0

9p2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

p=0(rejected) or p=4