Question

For what value of P the quadratic equation X square mines PX plus 4 equals to zero has equal roots

Answer 1

Answer:

Step-by-step explanation:

X^2- px +4 =0

For equal roots discriminant must be equals to 0

i.e. D= b^2-4ac = 0

In this question

a = 1

b = -p

C = 4

Now, (-p)^2 -4×1×4= 0

P^2 - 16 = 0

P^2= 16

P = root of 16

P= 4 or p = -4

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