Question

For what value of p, the sum of zeroes of the quadratic polynomial
x2 - (p+6)x + 2(2p + 1) is half of their product.​

Answer 1

Answer:

Step-by-step explanation:

Let α and β are the roots of given quadratic equation x² - ( k +6)x + 2(2k +1) = 0 [ you did mistake in typing of equation , I just correct it ]

Now, sum of roots = α + β = - {-( k + 6)}/1 = (k + 6)

product of roots = αβ = 2(2k + 1)/1= 2(2k + 1)

A/C to question,

sum of roots ( zeros ) = 1/2 × products of roots zeros

⇒ (k + 6) = 1/2 × 2(2k + 1)

⇒ (k + 6) = (2k + 1)

⇒ k + 6 = 2k + 1

⇒ k = 5

Hence, k = 5

Answer 2

Step-by-step explanation:

sum roots (zeroes) =1/2 x products of roots zeroes

=(k+6) 1/2x2 (2x+7

=(k+6) =( 2k +1)

=k+6=2k+1

k=5

hence, k=5

friends I hope this answer help you