for what value of P the system of equations 4x+py+8=0 and 2x+2y+2=0 have no solutions
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Answered by
0
Answer:
myiuufffzzsr has a wide range
Answered by
2
Step-by-step explanation:
Given equation:-
4x+py+8=0
a
1
=4,b
1
=p,c
1
=8
2x+2y+2=0
a
2
=2,b
2
=2,c
2
=2
Since the given pair of equation hs unique solution.
Therefore,
a
2
a
1
=
b
2
b
1
2
4
=
2
p
⇒p
=4
Hence the given pair of equation has unique solution for all values of p except 4.
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