For what value of P,the three points (3,2),(4,p) and (5,3) are collinear?
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Question:-
For what value of P,the three points (3,2),(4,p) and (5,3) are collinear?
Method Of Solution;-
For Collinear!!
X1(y2-y3)+x2(y3-y1)+x3(y1-y2)
Substitute the Given value in Equation!!
X1(y2-y3)+x2(y3-y1)+x3(y1-y2) = 0
=> 3(p- 3) + 4(3-2) + 5(2-p) = 0
=> 3p-9 + 4(1) + 10-5p = 0
=> 3p-5p -9+4+10 = 0
=> -2p -9+14 = 0
=> -2p +5 = 0
=> -2p = -5
•°• p = 5/2
Hence, For value of p (5/2) ,the three points (3,2),(4,p) and (5,3) are collinear.
Question:-
For what value of P,the three points (3,2),(4,p) and (5,3) are collinear?
Method Of Solution;-
For Collinear!!
X1(y2-y3)+x2(y3-y1)+x3(y1-y2)
Substitute the Given value in Equation!!
X1(y2-y3)+x2(y3-y1)+x3(y1-y2) = 0
=> 3(p- 3) + 4(3-2) + 5(2-p) = 0
=> 3p-9 + 4(1) + 10-5p = 0
=> 3p-5p -9+4+10 = 0
=> -2p -9+14 = 0
=> -2p +5 = 0
=> -2p = -5
•°• p = 5/2
Hence, For value of p (5/2) ,the three points (3,2),(4,p) and (5,3) are collinear.
Answered by
0
X1(y2-y3)+x2(y3-y1)+x3(y1-y2) = 0
3(p- 3) + 4(3-2) + 5(2-p) = 0
3p-9 + 4(1) + 10-5p = 0
3p-5p -9+4+10 = 0
-2p -9+14 = 0
-2p +5 = 0
p = 5/2
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