For what value of p will the equation x²+ 6x+2p+1=0 have real roots?
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Answer:
2x^2+6x+p=0 has two real roots.
b^2-4a.c > 0
Putting a= 2 , b= 6 and c= p.
36–4.2.p >0
or. 8p - 36 < 0
or. p < 36/8
or. p < 9/2. Answer.
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