Question

for what value of p will the following pair of linear equations have infinitely many solution (p-3)x+3y=p px+py=12​

Answer 1

Step-by-step explanation:

a1=(p-3), a2=p

b1=3, b2=p

c1=-p, c2=-12

condition for infinitely many solution

a1/a2=b1/b2=c1/c2

(p-3)/p=3/p=-p/-12

let first a1/a2=b1/b2

(p-3)/p=3/p

p(p-3)=3p

p^2-3p=3p

p^2=3p+3p

p^2=6p

p=6

Hence p=6 for infinitely many solution