For what value of P will the following pair os linear equations have infinitely many solutions ( p-3)x +3y =P px +py=12
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Answer:
Step-by-step explanation:
(p-3)x +3y =p
px +py =12
Now for infinitely many solutions,
a1/a2 =b1/b2 = c1/c2
Thus, p-3/p = 3/p = p/12
So 3p=p^2 -3p & p^2=36
= p^2= 6p and p= root36
So, p=6 and p=6 or (-6)
6 satisfies both equations thus p=6
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