Math, asked by jsoem929, 10 months ago

for what value of p will the following system of equations have no solution?
(2p-1)x + (p-1)y = 2p + 1 ; y + 3x -1 = 0​

Answers

Answered by Anonymous
15

Heya...

Answer:

For (2p-1)x + (p-1)y - (2p+1) =0

a1=2p-1, b1 =p-1 and c1= -(2p+1)

and for 3x + y - 1 =0

a2 = 3, b2 = 1 and c2 = -1

The Condition for no solution is...

a1/a2 = b1/b2 = c1/c2

2p-1/3 = p-1/1 = 2p +1/1

2p - 1/3 = p-1/1

3p-3 = 2p-1

3p - 2p = 3-1

p=2

__________________________________

p-1/1 is not equal to 2p+1

p - 1= 2p + 1

p is not equal to -2

2p-1/3 = 2p+1/1

2p -1 = 6p +3

4p =-4

p = -1

Thanks ...✌️✌️✌️✌️

Answered by Anonymous
6

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Refer the attachment.

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