Question

For what value of p will the following system of equations has no solution (2p – 1)x + (p -1)y = 2p + 1 ; y + 3x – 1 = 0

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

The value of p is 2.

Given,

A system of equation (2p – 1)x + (p -1)y = 2p + 1 ; y + 3x – 1 = 0.

To Find,

The value of p such that the system of the equation has no solution.

Solution,

For a system of equation to have no solution

a₁/a₂ = b₁/b₂

Now, the given system of equation is

(2p – 1)x + (p -1)y = 2p + 1 ; y + 3x – 1 = 0

a₁ = 2p-1 , a₂ = 3, b₁ = p-1, b₂ = 1

Now, substituting the values

(2p-1)/3 = (p-1)/1

2p-1 = 3p-3

p = 3-1 = 2

Hence, the value of p is 2.

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