For what value of p, will the following system of linear equations represent parallel lines? -x+py=1 and px-y=1
(class 10 CBSE SAMPLE PAPER 2017-18 MATHS)
Answers
Answered by
82
SOLUTION:
Given pair of equation is
-x+py=1………….(1)
px-y=1……………(2)
On comparing the given Equations with standard form
a1x+b1y+c1=0 and a2x+b2y+c2=0
a1= -1, b1= p, c1=-1
a2=p, b2=-1, c2=-1
A pair of linear equations will represent parallel lines i.e have no solution ,if
a1/a2 = b1/b2 ≠ c1/c2
-1/p = p/-1 ≠ -1/-1……………..(3)
I II III
On taking I and II terms we get
-1/p = p/-1
p²=1
p= ±1
Since , p=-1 does not satisfy the last two terms of equation (3)
Therefore p= 1 is the required value.
Hence, for p= 1, the given system of equation will represent parallel lines
HOPE THIS WILL HELP YOU....
Given pair of equation is
-x+py=1………….(1)
px-y=1……………(2)
On comparing the given Equations with standard form
a1x+b1y+c1=0 and a2x+b2y+c2=0
a1= -1, b1= p, c1=-1
a2=p, b2=-1, c2=-1
A pair of linear equations will represent parallel lines i.e have no solution ,if
a1/a2 = b1/b2 ≠ c1/c2
-1/p = p/-1 ≠ -1/-1……………..(3)
I II III
On taking I and II terms we get
-1/p = p/-1
p²=1
p= ±1
Since , p=-1 does not satisfy the last two terms of equation (3)
Therefore p= 1 is the required value.
Hence, for p= 1, the given system of equation will represent parallel lines
HOPE THIS WILL HELP YOU....
Answered by
46
-x+py=1
px-y=1
a1=-1. b1=p. c1=1
a2=p. b2=-1. c2=1
if equation represent parallel line,
a1/a2=b1/b2≠c1/c2
a1/a2=b1/b2
-1/p=p/-1
p²=1
p=±1
b1/b2≠c1/c2
p/-1≠1/1
p≠-1
so,the value of p will be 1 for the equation represent parallel line.
px-y=1
a1=-1. b1=p. c1=1
a2=p. b2=-1. c2=1
if equation represent parallel line,
a1/a2=b1/b2≠c1/c2
a1/a2=b1/b2
-1/p=p/-1
p²=1
p=±1
b1/b2≠c1/c2
p/-1≠1/1
p≠-1
so,the value of p will be 1 for the equation represent parallel line.
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