Question

For what value of p will the following systems of linear equations have no solution. px+3y=1 and 12x+py=2.
Class 10

Answer 1

px+3y=1 --------------eq.1

12x+py=2 --------------eq.2

Let,

a1=p, b1=3, c1= -1

a2=12, b2=p, c2= -2

For no solution, the following set of equations will be,

a1/a2 = b1/b2 not equal to c1/c2

=> p/12 = 3/p

=> p^2 = 36

=> p = √36 = +6, -6

Therefore, p= 6 or p=-6

Ans. For p =6 and p= -6, the following systems of linear equations will have no solution.

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