For what value of p, x= 2 and y = 3 is a solution of (p+1) x – (2p+3)y –1 = 0? (a) Write the equation obtained. (b) How many solutions of this equation are possible? (c) Is this line passing through the point (–2, 3)? Justify.
Answers
Answered by
0
Answer:
Hi I am happy to meet you
Answered by
0
Answer:
the answer will be
x=2
y=3
(p+1)2-(2p+3)(3)-1=0
2p+2-6p-9-1=0
-4p-8=0
p=-2
Similar questions