Question

For what value of p ; x=2 , y=3 is a solution of [p+1]x-[2p+3]y-1=0

Answer 1

=> {(p+1)2} - {(2p+3)3} -1=0
=> {2p+2} - {6p+9} - 1=0
=>. 2p +2-6p-9-1=0
=>. -4p -8= 0
=> -4p = 8
=>. p = 8/-4
=>. p= -2