For what value of q, (-4) is a zero of the polynomial
x^2 –2x – (7q – 3) ?
Answers
Answered by
6
Answer:
27/7
Step-by-step explanation:
x^2-2x-(7q-3)
replace x by (-4)
(-4)^2-2(-4)-(7q-3)=0
16+8-7q+3=0
27-7q=0
27=7q
q=27/7
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