Question

for what value of r, the two equations x - 3y is equal to 1 and (4 -r)x - y + 1=0 would have no equation?

Answer 1

Answer:

Given: x-3y =1........(1)

And, (4-r)x-y+1=0....(2)

Multiplying (2) throughout by 3, we get

3(4-r)x-3y+3=0.......(3)

Now solving (1)and (3),

x-3y-1=0

(12-3r)x-3y+3=0

Subtracting (3) from (1) we get

x-(12-3r)x-4=0

Or,x-12x+3rx-4=0

Or, -11x+3rx=4

Or,x(-11+3r)=4

When r=11/3, there will be no equation