for what value of resistor x will be the equivalent resistance of two circuit shown to be the same
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wow good question and suprising
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Answer:
The value of resistance X is 2R.
Explanation:
Separate the two circuits with an imaginary line.
Clearly, both circuits are different after sections AB and CD.
So, resistances of two circuits are same, if
RAB=RCD
So, R + X = R + ( (6R (R + X) ) / (6R + R + X) )
⇒X = 7R + X6R (R+X)
⇒7RX + X^2 = 6X^2 + 6RX
⇒X^2 + RX − 6R^2 = 0
we know the formula,
X = (-b ± (b^2-4ac)^1/2) / 2a
⇒X = (−R ± R2−4 (1) (−6R2) ) / 2 (1)
X = (−R ± (25R^2)^1/2) / 2
or X = − R ± 5R / 2
∴ X=2R
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