Question

For what value of ‘s’, 3 is a zero of the polynomial 2x2 + x + (s – 3).

Answer 1

Answer:

S = -4

Step-by-step explanation:

2*2+(3)+(s-3) =0

4+3+(s-3)=0

7+(s-3)=0

s-3= -7

s = -7+3

s = -4

Check :

2*2+(3)+(-4-3)

7+ [-7]=o

Answer 2

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★ Given that,

For what value of ‘s’, 3 is a zero of the polynomial 2x² + x + (s – 3).

☯ The polynomial is,

↪ p(x) = 2x² + x + s - 3

↪ 3 is zero of the polynomial.Hence, p(x) = 3

★ So,

➡ 2(3)² + 3 + s - 3 = 0

➡ 2(9) + s = 0

➡ 18 + s = 0

➡ s = 0 - 18

➡ s = - 18

★ Verification,

Substitute the value of s on the polynomial.

➡ 2(3)² + 3 - 18 - 3

➡ 2(9) - 18

➡ 18 - 18

➡ 0

$\boxed{∴\;s = - 18}$

Step-by-step explanation:

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