For what value of ‘s’, 3 is a zero of the polynomial 2x2 + x + (s – 3).
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Answer:
Step-by-step explanation:
Put x=3 and equate polynomial to 0
Therefore,
2(3)² +3 + (s-3)=0
18+3-3+s=0
s=-18
Answered by
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P(x)=2x²+x+(s-3)
P(3)=2(3)²+3+s-3
=2x9+s+0=18+s
Now, here given that p(3)=0
18+s=0=>s=-18
Therefore,s=-18
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