Question

For what value of 't' the following pair of linear equations has no solution ?
2x - ty = 5 and 3x + 2y = 11​

Answer 1

✰ Qᴜēsᴛíõñ :-

For what value of 't' the following pair of linear equations has no solution ?

2x - ty = 5 and 3x + 2y = 11

✪ Söʟúᴛîøɴ :-

Pair of linear equations has no solution if

a1/a2 = b1/b2 ≠ c1/c2

➙ ⅔ = -t/2 ≠ -5/-11

➙ -3t = 4

➙ t = - 4/3

Answer 2

Answer:

-4/3

t = -4/3

Step-by-step explanation:

Given,

2x - ty = 5 ...... (i)

3x + 2y = 11 ...... (ii)

Here,

a1 = 2 , b1 = -t , c1 = 5

a2 = 3 , b2 = 2 , c2 = 11

We know that,

For No Solution :

a1/a2 = b1/b2 ≠ c1/c2

By applying values, we get

2/3 = (-t) / 2 ≠ 5/11

(a) = (b) ≠ (c)

If we compare firstly (a) and (b), then, we get,

=> 2/3 = (-t) / 2

=> (-t) = 4/3

=> t = -4/3

Now, if we compare (b) and (c), then we get,

(-t) / 2 ≠ 5/11

=> (-t) ≠ 10/11

=> t ≠ (-10) / 11

Here, it clearly shows that t ≠ (-10)/11.

Hence, the value of t = -4/3