Question

For what value of t the following pair of linear equations has a no solution ?2x-ty=5 and 3x+2y=11

Answer 1

No solution

a1/a2=b1/b2 but not equal to c1/c2

a1=2,b1=-t,c1=-5

a2=3,b2=2,c2=-11

2/3=-t/2

t= -4/3

Answer 2

Answer:

The required value of t is -4/3.

Step-by-step explanation:

Sine, if the system of two lines $a_1x+b_1y=c_1$ and $a_2x+b_2y=c_2$ has no solution,

Then,

$\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq \frac{c_1}{c_2}$

Given,

System of equations 2x-ty=5 and 3x+2y=11 has no solution,

$\implies \frac{2}{3}=\frac{-t}{2}\neq\frac{11}{5}$

$\implies \frac{2}{3}=-\frac{t}{2}\implies t = -\frac{4}{3}$

Since,

$\frac{4/3}{2}\neq\frac{11}{5}$

Hence, the required value of t is -4/3.