For what value of t, the point(2t,√t²-4) lies on x axis?
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Answer:
t=2
Step-by-step explanation:
(2t,√(t^2-4))
the point will be on x-axis only when ordinate value in the above point is zero.
implies that
√(t^2-4)=0
t^2-4=0
t^2=4
t=2
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