Question

for what value of the equation 9xsquare+6kx+4=0​ has no real root

Answer 1

Answer:

(-2,2)

Step-by-step explanation:

$9x {}^{2} + 6kx + 4 = 0$

has no real roots so

$b {}^{2} - 4ac < 0$

$(6k) {}^{2} - 4 \times 9 \times 4 < 0$

$36k {}^{2} - 144 < 0$

$k {}^{2} - 4 < 0$

$k \: belongs \: to \: ( - 2 \: to \: 2)$