For what value of the K quadratic equation 2x²+Kx+3=0 has equal roots
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Answered by
9
Answer:
for k value ✓24 or 2✓6 has equal roots
Step-by-step explanation:
we know if a quadratic equations have equal roots then b^2 - 4ac= 0
here a=2, b=k,c=3
by putting values
b^2-4ac=0
(k)^2-4(2)*(3)=0
k^2 -24=0
k=√24
k=✓2*2*2*3
k=✓(2)^2 x 6
k=2✓6
Answered by
44
We have to find the values of K for quadratic equation 2x² + Kx + 3 = 0 , so that they have 2 equal roots.
Quadratic equation will be equal only when,
Discriminant, D = b² - 4ac = 0
On comparing 2x² + Kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get , a = 2 , b = k , c = 3
So, discriminant, D = ( k )² - 4 ( 3 ) ( 2 ) = 0
Or k² - 24 = 0
Or k = ± √24 = ± 2√6
Hence , the value of k = 2√6 or - 2√6.
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