Question

For what value of the K quadratic equation 2x²+Kx+3=0 has equal roots​

Answer 1

Answer:

for k value ✓24 or 2✓6 has equal roots

Step-by-step explanation:

we know if a quadratic equations have equal roots then b^2 - 4ac= 0

here a=2, b=k,c=3

by putting values

b^2-4ac=0

(k)^2-4(2)*(3)=0

k^2 -24=0

k=√24

k=✓2*2*2*3

k=✓(2)^2 x 6

k=2✓6

Answer 2

$\huge\bold{Answer :-}$

We have to find the values of K for quadratic equation 2x² + Kx + 3 = 0 , so that they have 2 equal roots.

Quadratic equation will be equal only when,

Discriminant, D = b² - 4ac = 0

On comparing 2x² + Kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get , a = 2 , b = k , c = 3

So, discriminant, D = ( k )² - 4 ( 3 ) ( 2 ) = 0

Or k² - 24 = 0

Or k =  ± √24 =  ± 2√6

Hence , the value of k = 2√6 or - 2√6.