Question

For what value of λ, the matrix [1λ03−12415] is singular ?

Answer 1

Step-by-step explanation:

5−x

2

λ+1

4

∣

∣

∣

∣

∣

∣

is singular

⇒

∣

∣

∣

∣

∣

∣

5−λ

2

λ+1

4

∣

∣

∣

∣

∣

∣

⇒ 4(5−λ)−2(λ+1)=0

⇒ 20−4λ−2λ−2=0

⇒ −6λ=−18

⇒ λ=3

∴ For λ=3, the given matrix is singular