for what value of W will the polynomial p(x)=x^3+6x^2+wx-4 have the same reminder when it is divided by x+2andx-1
Answers
Answered by
3
Answer:
Here, g(x)=3x−1. To apply Remainder theorem, (3x−1) should be converted to (x−a) form.
∴3x−1=
3
1
(3x−1)=x−
3
1
∴g(x)=(x−
3
1
)
By remainder theorem, r(x)=p(a)=p(
3
1
)
p(x)=x
3
−6x
2
+2x−4⇒p(
3
1
)=(
3
1
)
3
−6(
3
1
)
2
+2(
3
1
)−4
=
27
1
−
9
6
+
3
2
−4=
27
1−18+18−108
=
27
−107
∴ the remainder p(
3
1
)=−
27
107
Step-by-step explanation:
hope it maybe helpful for you
Answered by
1
Step-by-step explanation:
Here, g(x) = 3x - 1. To apply Remainder theorem, (3x - 1) should be converted to(x - a) form.
- 3x – 1= (3x 3 (3x - 1) =X ..g(x) =
(x - 1²3)
By remainder theorem, r(x) = p(a) = p
p(x) = x³ - 6x² + 2x − 4 P (³3) =
2 6 3 +2 - 4
1 27 6 2 + 9 3 4= 118+18 - 108
27
-107
27
...the remainder p (3)
= -107/27
hope it will help you
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