for what value of x:2x, x+10 and 3x+2 are an AP
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x+10 - 2x = 3x+2-(x+10)
This is because d(common difference) = T2 - T1
-x +10 = 2x - 8
10 +8 = 3x
x =6
HOPE IT HELPS YOU
This is because d(common difference) = T2 - T1
-x +10 = 2x - 8
10 +8 = 3x
x =6
HOPE IT HELPS YOU
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