for what value of x, a number of the form (x ×100+6×10+8) is divisible by 3
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when a number is divisible by 3 then the sum of the digits is also divisible by 3
here the digits are x,6 and 8
so, x+6+8=14+x
if x=1 then sum is 15 which is divisible by 3
if x=4 then sum is 18 which is divisible by 3
if x=7 then sum is 21 which is divisible by 3
so the values of x are 1 , 4 , 7
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