For what value of x are 2x+1, 13, 5x-2 are three consecutive terms of an
a.P
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As we know that the C.D of an A.P are equal
∴d1 = d2
∵a2-a1=a3-a2
⇒13-(2x+1)=5x-2-13
⇒13-2x-1=5x-15
⇒12+15=5x-2x
⇒27=3x
⇒x=27/3
⇒x=3
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