Question

For what value of x are 2x++1,13,5x-3 three consecutive terms of AP?

Answer 1

Hii !!




First term ( a ) = 2x + 1


Second term ( a2 ) = 13


And,

Third term ( a3 ) = 5x - 3




We know that,

Common difference ( d ) = Second term - first term..





= a2 - a1





=> 13 - ( 2x + 1 )



=> 13 - 2X - 1


=> 12 - 2X


Common difference ( d ) = 12 - 2x



Also,


Common difference ( d ) = Third term - second term.



=> 5x - 2 - 13


=> 5x - 15

Common difference ( d) = 5x - 15


We all know that , the common difference of an AP is always equal.


So,




12 - 2X = 5x - 15



5x + 2x = 15 + 12




7x = 17


X = 17/7.

Answer 2

thank you ...I hope I gave correct answer