Question

for what value of x are 2x - 1 , 7 and 3 x three consecutive terms of an ap​

Answer 1

$x = 3$

a2-a1=a3-a2

7-(2x-1)=3x-7

7-2x+1=3x-7

8-2x=3x-7

transposing -2x to RHS and -7 to LHS,we get

8+7 =3x+2x

15=5x

x=15/5

x =3