for what value of x, is 3 is a zero of the polynoimal 2x^2+x+k.
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2x^2+x+k.
P(x) = 2x^2+x+k
P(3)= 2(3)^2+3+k
=18+3+k
21+k =0
=>k= -21
Hope this helps
Thank you
Answered by
0
Answer:
Step-by-step explanation:
Substitue 3 in the equation
2.(3)^2 + (3) + k = 0
2.(9) + 3 + k = 0
18 + 3 + k = 0
21 + k = 0
K = -21
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