Math, asked by kapilsachdeva9317, 10 months ago

for what value of x, is 3 is a zero of the polynoimal 2x^2+x+k.

Answers

Answered by Abhik05
0

2x^2+x+k.

P(x) = 2x^2+x+k

P(3)= 2(3)^2+3+k

=18+3+k

21+k =0

=>k= -21

Hope this helps

Thank you

Answered by danishjibran
0

Answer:

Step-by-step explanation:

Substitue 3 in the equation

2.(3)^2 + (3) + k = 0

2.(9) + 3 + k = 0

18 + 3 + k = 0

21 + k = 0

K = -21

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