Question

For what value of x is sin x = cos 19°, where 0°< x < 90°?

Answer 1

x=71 degree. HOPE THIS WILL HELP YOU.

Answer 2

Sin x = cos 19° ; 0° < x < 90°

cos is the complementary of sine. This means that the value of x in sin x and the value of 19° in cos 19° adds up to 90°

x + 19° = 90°
x = 90° - 19°
x = 71°

sin 71° = cos 19°
0.9455 = 0.9455

The value of x is 71°