Question

for what value of x p(x)=0 ,p(x)=x3 ,
-2x2+5x-4​

Answer 1

I have given the attachment

Answer 2

Given:

Given the above equation

$p(x)=x^3,-2x^2+5x-4$

The value of

$p(x)=0$

Find out:

Find the value of x for given equation

Step-by-step explanation:

• For get the value of x we have p(x)=0

• The equations for (x)

   $P(x)=x^3-2x^2+5x-4\\x^3-2x^2+5x-4=0$

• 0 is the constant for coefficient (x)

     If $x=1$

    $p(1)=(1)^3-2(1)^2+5(1)-4\\p(1)=1-2+5-4\\p(1)=2\\p=2$

• The value of p=2
• Then the value of p(x)=0

    $p=2\\2x=0\\x=\frac{0}{2}\\ x=0$

The value of x is 0.