Math, asked by Ravikishore8511, 2 months ago

For what value of x? The angles x+15, x_15 and x+60 are the angles of a triangles

Answers

Answered by Anonymous

For what value of x, the angles (x+15)°, (x-15)° and (x+60)° are the angles of a triangles?

Value of x = 40° .

We have given three angles of triangle which are as :

(x+15)°, (x-15)°, (x+60)° respectively.

Now,

We know that sum of all interior angles of traingle is always equal to 180°.

Therefore,

We can say that (x+15)° + (x-15)°+ (x+60)° is equal to 180°. •••••••( 1)

Now, to find value of x we have to Solve it.

(x+15)° +(x-15)°+ (x+60)° = 180°

=> x + x + x + 15- 15 + 60 = 180°

=> 3x +60 = 180°

=> 3x = 180° - 60°

=> 3x = 120°

=> x = 120/3

=> x = 40°

To verify our answer, we have to put value of x ( 40°) in equation 1.

(x+15)° + (x-15)°+ (x+60)° = 180°

=> (40+15)° +(40-15)°+(40+60)° = 180°

=> 55° + 25° + 100° = 180°

=> 80° + 100° = 180°

=> 180° = 180°

∴ LHS = RHS

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