for what value of x will 2x+1/3x-2 and 3x-4/x+8 represent the same fraction also find the fraction
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Answered by
61
Hi ,
It is given that ,
( 2x + 1 )/( 3x - 2 ) = ( 3x - 4 )/( x + 8 )
( 2x + 1 )( x + 8 ) = ( 3x - 4 )( 3x - 2 )
2x² + 16x + x + 8 = 9x² - 6x - 12x + 8
2x² + 17x + 8 = 9x² - 18x + 8
0 = 9x² - 18x + 8 - 2x² - 17x - 8
0 = 7x² - 35x
7x² - 35x = 0
7x( x - 5 ) = 0
Therefore ,
7x = 0 or x - 5 = 0
x = 0 or x = 5
I hope this helps you.
: )
It is given that ,
( 2x + 1 )/( 3x - 2 ) = ( 3x - 4 )/( x + 8 )
( 2x + 1 )( x + 8 ) = ( 3x - 4 )( 3x - 2 )
2x² + 16x + x + 8 = 9x² - 6x - 12x + 8
2x² + 17x + 8 = 9x² - 18x + 8
0 = 9x² - 18x + 8 - 2x² - 17x - 8
0 = 7x² - 35x
7x² - 35x = 0
7x( x - 5 ) = 0
Therefore ,
7x = 0 or x - 5 = 0
x = 0 or x = 5
I hope this helps you.
: )
Answered by
14
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