for what value of x will 2x + 1/ 3x -2 and 3x- 4/x+8 represent the same fraction?Also find the friction.
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2x+1/3x-2=3x-4/x+8
change the denominator to each other
=x+8(2x+1)=3x-2(3x-4)
=2x^2+x+16x+8=9x^2-12x-6x+8
=2x^2+17x+8=9x^2-18x+8
=17x+18x+8-8=9x^2-2x^2
=35x=7x^2
=7x^2-35x+0=0
=7x^2-35x-0x+0=0
=7x(x-5)-0(x+0)=0
7x-0=0
x=7 answer
x-5=0
x=5 answer
change the denominator to each other
=x+8(2x+1)=3x-2(3x-4)
=2x^2+x+16x+8=9x^2-12x-6x+8
=2x^2+17x+8=9x^2-18x+8
=17x+18x+8-8=9x^2-2x^2
=35x=7x^2
=7x^2-35x+0=0
=7x^2-35x-0x+0=0
=7x(x-5)-0(x+0)=0
7x-0=0
x=7 answer
x-5=0
x=5 answer
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