Question

for what value of x:(x+1),3xand (4x+2) are in AP​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

If they are in AP the difference between the consecutive terms will be constant......

considering the first two terms,

$= > 3x - (x + 1) = 2x - 1$

-----> eq 1

Considering the next 2 terms,

$4x + 2 - 3x = x + 2$

-----> eq 2

Equating eq 1 and 2,

$2x - 1 = x + 2$

$= > x = 3$