Question

For what value of x, x + 2, 4 x minus 6 and 3 x minus 2 are the three consecutive term of ap for 0

Answer 1

Answer:

x = 3

Step-by-step explanation:

Given that-

(x + 2), (4x - 6) and (3x - 2)

We know that- If a, b and c are in A.P. then-

$b = \dfrac{a+c}{2}$

So, $4x - 6 = \dfrac{(x+2)+(3x - 2)}{2}$

2(4x - 6) = x + 2 + 3x - 2

8x - 12 = 4x

8x - 4x = 12

4x = 12

x = 3

Hence, for x = 3, (x + 2), (4x - 6) and (3x - 2) are the three consecutive terms of A.P.