For What value of x,
x² +8x + 163 is a perfect cube?
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Answered by
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Answer:
If X=10
10^2+8×10+163=100+80+163=
343=7^3
7^3 IS A PERFECT CUBE
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Step-by-step explanation:
Answer:
If X=10
10^2+8×10+163=100+80+163=
343=7^3
7^3 IS A PERFECT CUBE
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