Question

For what value of y is the perimeter of shape 220 cm?​

Answer 1

Question:

Find the value of $y$.

Given,

Length = $5y+4$

Breadth = $2y+36$

Perimeter = $220$

Now,

$2(5y+4+2y+36) = 220$

$2(5y+2y+36+4)= 220$

$2(7y+40)=220$

$14y + 80=220$

$14y=220-80$

$14y=140$

$y=140\div14$

$y=10$

Verification,

LHS = $2(5y+4+2y+36)$

= $2(5$ × $10+4+2$ × $10+36)$

= $2(50+4+20+36)$

= $2(54+56)$

= $2$ × $110$

= $220$

RHS = $220$

LHS = RHS hence, verified.

Thus,

The value of $y$ is $10$.

Therefore,

Length = $5y+4$

= $5$ × $10+4$

= $50+4$

= $54cm$

Breadth = $2y+36$

= $2$ × $10+36$

= $20+36$

= $56cm$

Hence,

Length = 54 cm

Breadth = 56 cm

Hope it helps