Question

For what value p, -4 is a zero of p(x)=x^2-x-(2p+2)

Answer 1

Answer:

-9

Step-by-step explanation:

p(x)=x²-x-(2p+2)

p(-4)=(-4)²-(-4)-(2p+2)

p(-4)=16+4-2p-2

p(-4)=20-2-2p

p(-4)=18-2p

-4p+2p=18

-2p=18

p,=-18/2

p=-9

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