For what value(s) of 'a' quadratic equation
30 ax square - 6x +1=0 has no real roots?
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Answer:
'a' can have the value of any natural number.
Step-by-step explanation:
The equation is;
30 ax^2 - 6x +1=0
Its given that it has no real root.
Thus, for no real roots, the equation we use is:
= b^2 - 4ac < 0 (i)
Thus, using given and eq.(i), it can be deduced;
= (6)^2 - 4(30a)(1) < 0
= 36 - 120a < 0
Value of 'a' can be any natural number.
That's all.
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