For what value(s) of 'a' quadratic equation 30 ax2 - 6x +1 = 0 has no real
roots?
Answers
Answered by
12
EXPLANATION.
quadratic equation = 30ax² - 6x + 1 = 0.
Equation has no real roots.
[ D < 0 Or b² - 4ac < 0 ].
→ (-6)² - 4(30a)(1) < 0.
→ 36 - 120a < 0.
→ 36 > 120a
→ 36/120 > a.
→ 3/10 > a.
More information.
(1) = D = 0 [ b² - 4ac = 0 ]
Roots are real and equal.
(2) = D < 0 [ b² - 4ac < 0 ]
Roots are imaginary.
(3) = D > 0 [ b² - 4ac > 0 ]
Roots are real and unequal.
Answered by
40
Question :-
For what value of 'a' , quadratic equation 30ax² - 6x + 1 = 0 has no real roots?
Answer :-
If the quadratic equation has no real roots, then the value of discriminant (D) is less than 0.
Here,
- a = 30a
- b = -6
- c = 1
➩
➩
➩
➩
➩
➩
Similar questions
English,
2 months ago
Computer Science,
4 months ago
Math,
10 months ago
Math,
10 months ago
Chemistry,
10 months ago