Question

For what value(s) of ‘a’ quadratic equation 30 x2 − 6 + 1 = 0 has no real roots?

Answer 1

Answer:

Step-by-step explanation:

Given quadratic equation is 30 a x² - 6 x + 1 = 0

Since, when equation will have no real roots then, Discriminant of this equation will be less than zero

so,

→ Discriminant = (-6)² - 4 (30 a) (1) < 0

→ (-6)² - 4 (30 a) (1) < 0

→ 36 - 120 a < 0

→ 36 < 120 a

→ 120 a > 36

→ a > 36 / 120

→ a > 3 / 10

Therefore,

For values of 'a' greater than 3/10, given quadratic equation will have no real roots.

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