Math, asked by krishnatalukdar1, 6 months ago

For what value(s) of ‘a’ quadratic equation 30ax^2 − 6x + 1 = 0 has no real roots?​

Answers

Answered by anurag333ag
1

Answer:

A should be less than 30/9

Answered by harshita620911
0

Answer:

> a > 3

Step-by-step explanation:

30ax^2 − 6x + 1 = 0

( - 6 )^2 - 4 ( 3a ) ( 1 ) < 0

12a > 36 = > a > 3

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