For what value(s) of ‘a’ quadratic equation 30ax^2 − 6x + 1 = 0 has no real roots?
Answers
Answered by
1
Answer:
A should be less than 30/9
Answered by
0
Answer:
> a > 3
Step-by-step explanation:
30ax^2 − 6x + 1 = 0
( - 6 )^2 - 4 ( 3a ) ( 1 ) < 0
12a > 36 = > a > 3
Similar questions