Question

For what value(s) of ‘a’ quadratic equation 30ax2

– 6x + 1 = 0 has real and equal roots?​

Answer 1

Step-by-step explanation:

for real and equal roots the discriminant of the equation should be zero

p(x) = 30ax² -6x +1

Discriminant = b² - 4ac

0 = 6² - 4 ×30a × 1

0 = 36 - 120 a

120a= 36

a= 5

Hence the value of a should be 5 so as to get real and equal roots.