For what value(s) of ‘a’, the quadratic equation 30 2 − 6 + 1 = 0 has no real roots?
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Question -> For what value(s) of ‘a’, the quadratic equation 3ax² - 6x + 1 = 0 has no real roots?
Solution : here quadratic equation is 3ax² - 6x + 1 = 0,
Discriminant, D = (6)² - 4(3a)(1)
= 36 - 12a
A/c to question,
Quadratic equation has no real roots.
so, D < 0
⇒36 - 12a < 0
⇒12(3 - a) < 0
⇒3 - a < 0
⇒3 < a
Therefore the value of a belongs to (3, ∞)
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