Math, asked by Anonymous, 8 months ago

For what value(s) of ‘a’, the quadratic equation 30 2 − 6 + 1 = 0 has no real roots?

Answers

Answered by abhi178
3

Question -> For what value(s) of ‘a’, the quadratic equation 3ax² - 6x + 1 = 0 has no real roots?

Solution : here quadratic equation is 3ax² - 6x + 1 = 0,

Discriminant, D = (6)² - 4(3a)(1)

= 36 - 12a

A/c to question,

Quadratic equation has no real roots.

so, D < 0

⇒36 - 12a < 0

⇒12(3 - a) < 0

⇒3 - a < 0

⇒3 < a

Therefore the value of a belongs to (3, ∞)

also read similar questions : If -3 is the root of quadratic equation 2x^2 + px - 15 = 0, while the quadratic equation x^2 - 4px + k = 0 ha...

https://brainly.in/question/15995618

For what value of k will the following equation has no solutions?

3x + y = 1

(2k - 1)x + (k - 1)y = 2k+1

https://brainly.in/question/1296813

Similar questions