Question

For what value(s) of 'd' quadratic equation 3ax2 - 6x + 1 = 0 has no real roots ?
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Answer 1

Step-by-step explanation:

if the eq has no real roots then duceiminant must be greater than 0

so b²-4ac> 0

here b=6. a= 3a. c= 1

therefore 6²-4*3a*1 >. 0

36 - 12a. >0

-12a. > -36

12a. < 36

a< 36/12

a< 3