Question

For what value(s) of k, (8k + 1)x2 + (2k + 4)x + (4 – k) is a perfect square?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

This a quadratic equation in x with A=(4−k) , B = (2k+4) and C = (8k+1)

For a perfect square, Discriminant = B2−4AC=0

=>(2k+4)2−4(4−k)(8k+1)=0

=>(4k2+16k+16)−4(32k+4−8k2−k)=0

=>k2(4+32)+k(+16−124)+(16–16)=0

=>36k2−108k=0=>36k(k−3)=0

=> k = 0 or k = 3